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信息安全工程師每日一練試題(2024/2/10)

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信息安全工程師每日一練試題內(nèi)容(2024/2/10)

  • 試題1

    為防范國(guó)家數(shù)據(jù)安全風(fēng)險(xiǎn),維護(hù)國(guó)家安全,保護(hù)公共利益,2021年7月,中國(guó)網(wǎng)絡(luò)安全審查辦公室發(fā)布公告,對(duì)“滴滴出行”“運(yùn)滿滿”“貨車幫”和“BOSS直聘”開展網(wǎng)絡(luò)安全審查。此次審查依據(jù)的國(guó)家相關(guān)法律法規(guī)是(   )。
    A.《中華人民共和國(guó)網(wǎng)絡(luò)安全法》和《中華人民共和國(guó)國(guó)家安全法》
    B.《中華人民共和國(guó)網(wǎng)絡(luò)安全法》和《中華人民共和國(guó)密碼法》
    C.《中華人民共和國(guó)數(shù)據(jù)安全法》和《中華人民共和國(guó)網(wǎng)絡(luò)安全法》
    D.《中華人民共和國(guó)數(shù)據(jù)安全法》和《中華人民共和國(guó)國(guó)家安全法》

    查看答案

    試題參考答案:A

    試題解析與討論:www.xomuzic.com/st/5222512951.html

  • 試題2

    《計(jì)算機(jī)信息系統(tǒng)安全保護(hù)等級(jí)劃分準(zhǔn)則》(GB17859-1999)中規(guī)定了計(jì)算機(jī)系統(tǒng)安全保護(hù)能力的五個(gè)等級(jí),其中要求對(duì)所有主體和客體進(jìn)行自主和強(qiáng)制訪問(wèn)控制的是(  )。
    A.用戶自主保護(hù)級(jí)
    B.系統(tǒng)審計(jì)保護(hù)級(jí)
    C.安全標(biāo)記保護(hù)級(jí)
    D.結(jié)構(gòu)化保護(hù)級(jí)

    查看答案

    試題參考答案:D

    試題解析與討論:www.xomuzic.com/st/3892624867.html

  • 試題3

    用戶在實(shí)際應(yīng)用中通常將入侵檢測(cè)系統(tǒng)放置在防火墻內(nèi)部,這樣可以( )。
    A.增強(qiáng)防火墻的安全性
    B.?dāng)U大檢測(cè)范圍
    C.提升檢測(cè)效率
    D.降低入侵檢測(cè)系統(tǒng)的誤報(bào)率

    查看答案

    試題參考答案:D

    試題解析與討論:www.xomuzic.com/st/57379669.html

  • 試題4

    Trust is typically interpreted as a subjective belief in the reliability, honesty and  security  of an entity on which we depend ( )our welfare .In online environments we depend on a wide spectrun of things , ranging from computer hardware,software and data to people and organizations. A security solution always assumes certain entities function according to specific policies.To trust is precisely to make this sort of assumptions , hence , a trusted entity is the same as an entity that is assumed to function according to  policy . A consequence of this is that a trust component of a system must work correctly in order   for the security of that system to hold, meaning that when a trusted(  )fails , then the sytems and applications that depend on it can(  )be considered secure.An often cited articulation of this principle is:" a trusted system or component is one that can break your security policy” ( which happens when the trust system fails ). The same applies to a trusted party such as a service provider ( SP for short )that is , it must operate according to the agreed or assumed   policy in order to ensure the expected level of securty and quality of services . A paradoxical   conclusion to be drawn from this analysis is that security assurance may decrease when increasing the number of trusted components and parties that a service infrastructure depends on . This is because the security of an infrastructure consisting of many.
    Trusted components typically follows the principle of the weakest link , that is ,in many situations the the overall security can only be as strong as the least reliable or least secure of all the trusted components. We cannot avoid using trusted security components,but the fewer the better. This is important to understand when designing the  identity management architectures,that is, fewer the trusted parties in an identity management model , stronger the security that can be achieved by it.
    The transfer of the social constructs of identity and trust into digital and computational concepts helps in designing and implementing large scale online markets and communities,and also plays an important role in the converging mobile and Internet environments.Identity management (denoted Idm hereafter ) is about recognizing and verifying the correctness of identitied in online environment .Trust management becomes a component of (  )whenever different parties rely on each other for identity provision and authentication . IdM and Trust management therefore depend on each other in complex ways because the correctness of the identity itself must be trusted for the quality and reliability of the corresponding entity to be trusted.IdM is also an essential concept when defining  authorisation policies in personalised services.
    Establishing trust always has a cost, so that having  complex trust requirement typically leads to high overhead in establishing the required trust. To reduce costs there will be incentives for stakeholders to “cut corners”regarding trust requirements ,which could lead to inadequate security . The challenge is to design IdM systems with relatively simple trust requirements.Cryptographic mechanisms are often a core component of IdM solutions,for example,for entity and data authentication.With cryptography,it is often possible to propagate trust from where it initially exists to where it is needed .The establishment of initial(  )usually takes place in the physical world,and the subsequent propagation of trust happens online,often in an automated manner.
    (71)A.with
    B. on
    C. of
    D. for
    (72)A.entity
    B.person
    C.component
    D.thing
    (73)A. No longer
    B. never
    C. always
    D.often
    (74)A. SP
    B. IdM
    C.Internet
    D.entity
    (75)A.trust
    B.cost
    C.IdM
    D. solution

    查看答案

    試題參考答案:D、C、A、B、A

    試題解析與討論:www.xomuzic.com/st/389944612.html

  • 試題5

    操作系統(tǒng)的安全審計(jì)是指對(duì)系統(tǒng)中有關(guān)安全的活動(dòng)進(jìn)行記錄、檢查和審核的過(guò)程,為了完成審計(jì)功能,審計(jì)系統(tǒng)需要包括(  )三大功能模塊。
    A.審計(jì)數(shù)據(jù)挖掘,審計(jì)事件記錄及查詢、審計(jì)事件分析及響應(yīng)報(bào)警
    B.審計(jì)事件特征提取、審計(jì)事件特征匹配、安全響應(yīng)報(bào)警
    C.審計(jì)事件收集及過(guò)濾、審計(jì)事件記錄及查詢,審計(jì)事件分析及響應(yīng)報(bào)警系統(tǒng)
    D.日志采集與挖掘、安全事件記錄及查詢、安全響應(yīng)報(bào)警

    查看答案

    試題參考答案:C

    試題解析與討論:www.xomuzic.com/st/3896821058.html

  • 試題6

    以下關(guān)于BLP安全模型的表述中, 錯(cuò)誤的是()
    A.BLP模型既有自主訪問(wèn)控制,又有強(qiáng)制訪問(wèn)控制
    B.BLP模型是一個(gè)嚴(yán)格形式化的模型,并給出了形式化的證明
    C.BLP模型控制信息只能由高向低流動(dòng)
    D.BLP是一種多級(jí)安全策略模型

    查看答案

    試題參考答案:C

    試題解析與討論:www.xomuzic.com/st/502065741.html

  • 試題7

    通用入侵檢測(cè)框架模型(CIDF)由事件產(chǎn)生器、事件分析器、響應(yīng)單元和事件數(shù)據(jù)庫(kù)四個(gè)部分組成。其中向系統(tǒng)其他部分提供事件的是(    )
    A.事件產(chǎn)生器
    B.事件分析器
    C.響應(yīng)單元
    D.事件數(shù)據(jù)庫(kù)

    查看答案

    試題參考答案:A

    試題解析與討論:www.xomuzic.com/st/5226223863.html

  • 試題8

    SM4算法是國(guó)家密碼管理局于2012年3月21日發(fā)布的一種分組密碼算法,在我國(guó)商用密碼體系中,SM4主要用于數(shù)據(jù)加密。SM4算法的分組長(zhǎng)度和密鑰長(zhǎng)度分別為().
    A.128位和64位
    B.128位和128位
    C.256位和128位
    D.256位和256位

    查看答案

    試題參考答案:B

    試題解析與討論:www.xomuzic.com/st/5020222146.html

  • 試題9

    對(duì)于定義在GF(p)上的橢圓曲線,取素?cái)?shù)P=11,橢圓曲線y2=x3+x+6mod11,則以下是橢圓曲線11平方剩余的是(  )。
    A.x=1
    B.x=3
    C.x=6
    D.x=9

    查看答案

    試題參考答案:B

    試題解析與討論:www.xomuzic.com/st/3898520398.html

  • 試題10

    安卓的系統(tǒng)架構(gòu)從上層到下層包括:應(yīng)用程序?qū)印?yīng)用程序框架層、系統(tǒng)庫(kù)和安卓運(yùn)行時(shí)、Linux內(nèi)核。其中,文件訪問(wèn)控制的安全服務(wù)位于()
    A.應(yīng)用程序?qū)?br />B.應(yīng)用程序框架層
    C.系統(tǒng)庫(kù)和安卓運(yùn)行時(shí)
    D.Linux內(nèi)核

    查看答案

    試題參考答案:D

    試題解析與討論:www.xomuzic.com/st/327164848.html

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