試題1

In a world where it seems we already have too much to do, and too many things to think about, it seems the last thing we need is something new that we have to learn.
But use cases do solve a problem with requirements: with （1 ） declarative requirements it's hard to describle steps and sequences of events.
Use cases, stated simply, allow description of sequences of events that, taken together, lead to a system doing something useful. As simple as this sounds, this is important. When confronted only with a pile of requiements, it's often（2 ）to make sense of what the authors of the  requirements really wanted the system to do. In the preceding example, use cases reduce the ambiguity of the requirements by specifying exactly when and under what conditions certain behavior occurs; as such, the sequence of the behaviors can be regarded as a requirement. Use cases are particularly well suited to capture approaches. Although this may sound simple, the fact is that (3 ) requirement capture approaches, with their emphasis on declarative requirements and "shall" statements, completely fail to capture fail to capture the (4 ) of the system's behavior. Use cases are a simple yet powerful way to express the behavior of the system in way that all stakeholders can easily understand.
But, like anything, use cases come with their own problems, and as useful as they are, they can be (5 ). The result is something that is as bad, if not worse, that the original problem. Therein it's important to utilize use cases effectively without creating a greater problem than the one you started with.
（1）A.plenty
B.loose
C.extra
D.strict
（2）A.impossible
B.possible
C.sensible
D.practical
（3）A.modern
B.conventional
C.different
D.formal
（4）A.statics
B.nature
C.dynamics
D.originals
（5）A.misapplied
B.applied
C.used
D.powerful

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試題2

系統(tǒng)中有R類資源m個，現(xiàn)有n個進程互斥使用。若每個進程對R資源的最大需求為w，那么當m、n、w分別取下表中的值時，對于表中的①～⑥種情況，  （1） 可能會發(fā)生死鎖。若將這些情況的m分別加上  （2）  ，則系統(tǒng)不會發(fā)生死鎖。

（1）A．①②⑤
B．③④⑤
C．②④⑤
D．②④⑥
（2）A．1、1和1
B．1、1和2
C．1、1和3
D．1、2和1

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試題3

在軟件開發(fā)過程中，系統(tǒng)測試階段的測試目標來自于（）階段，
A．需求分析
B．概要設計
C．詳細設計
D．軟件實現(xiàn)

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試題4

下圖所示平衡二叉樹（樹中任一結點的左右子樹高度之差不超過1）中，結點A的右子樹AR高度為h，結點B的左子樹BL高度為h，結點C的左子樹CL、右子樹CR高度都為h-1。若在CR中插入一個結點并使得CR的高度增加1，則該二叉樹 （ ） 。

A、以B為根的子二叉樹變?yōu)椴黄胶?
B、以C為根的子二叉樹變?yōu)椴黄胶?
C、以A為根的子二叉樹變?yōu)椴黄胶?
D、仍然是平衡二叉樹

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試題5

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試題6

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試題7

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試題8

與多模光纖相比較，單模光纖具有（ ）等特點。
A、較高的傳輸率、較長的傳輸距離、較高的成本
B、較低的傳輸率、較短的傳輸距離、較高的成本
C、較高的傳輸率、較短的傳輸距離、較低的成本
D、較低的傳輸率、較長的傳輸距離、較低的成本

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試題9

某個計算機中心有28臺微機，每臺微機有24個應用，每個應用占用1個端口地址，則這個計算機中心所有應用的地址總數(shù)為（ ）。
A、24 
B、28 
C、52 
D、672 

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試題10

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