午夜无码中文字幕影院,国产自产第一区c国产,久久久久久夜精品精品免费,国产99久久,夜夜夜夜曰天天天天拍国产,欧美日韩亚洲另类专区,国产精品区一区二区免费

軟題庫 培訓(xùn)課程
當(dāng)前位置:信管網(wǎng) >> 在線考試中心 >> 網(wǎng)絡(luò)工程師題庫 >> 試題查看
試卷年份2012年下半年
試題題型【單選題】
試題內(nèi)容

Let us now see how randomization is done when a collision occurs . After a (1), time is divided into discrete slots whose length is equal to the worst-case round-trip propagation time on ether. To accommodate the longest path allowed by Ethernet, the slot time has been set to 512 bit times, or 51.2us.
After the first collision, each station waits either 0 or 1 (2) times before trying again. If two stations collide and each one picks the same random number, they will collide again. After the second collision, each one picks either 0,1,2 or 3 at random and waits that number of slot times. If a third collision occurs (the probability of this happening is 0.25), then the next time the number of slots to wait is chosen at (3) from the interval 0 to 23-1.
In general, after I collisions, a random number between 0 and 2i -1 is chosen, and that number of slots is skipped. However, after ten collisions have been reached, the randomization (4) is frozen at a maximum of 1023 slots. After 16 collisions, the controller throws in the towel and reports failure back to the computer. Further recoveries up to (5) layers.

(1)A.datagram
 B.collision
 C.connection
D.service
(2)A.slot
 B.switch
 C.process
 D.fire
(3)A.rest
 B.random
 C.once
 D.odds
(4)A.unicast
 B.multicast
 C.broadcast
 D.interval
(5)A.local
 B.next
 C.higher
 D.lower

查看答案

相關(guān)試題